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27+33u-4u^2=0
a = -4; b = 33; c = +27;
Δ = b2-4ac
Δ = 332-4·(-4)·27
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-39}{2*-4}=\frac{-72}{-8} =+9 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+39}{2*-4}=\frac{6}{-8} =-3/4 $
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